(x^2-4x+13)=0

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Solution for (x^2-4x+13)=0 equation:


Simplifying
(x2 + -4x + 13) = 0

Reorder the terms:
(13 + -4x + x2) = 0

Remove parenthesis around (13 + -4x + x2)
13 + -4x + x2 = 0

Solving
13 + -4x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-13' to each side of the equation.
13 + -4x + -13 + x2 = 0 + -13

Reorder the terms:
13 + -13 + -4x + x2 = 0 + -13

Combine like terms: 13 + -13 = 0
0 + -4x + x2 = 0 + -13
-4x + x2 = 0 + -13

Combine like terms: 0 + -13 = -13
-4x + x2 = -13

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -13 + 4

Reorder the terms:
4 + -4x + x2 = -13 + 4

Combine like terms: -13 + 4 = -9
4 + -4x + x2 = -9

Factor a perfect square on the left side:
(x + -2)(x + -2) = -9

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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